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Find the derivative of f(x)\, with respect to x\,: f(x)={\frac  {\sin ^{2}x}{x^{3}}}\,

One trick to doing derivatives of quotients is to change them into a product. Here, {\frac  {\sin ^{2}x}{x^{3}}}=x^{{-3}}\sin ^{2}x\,, which is a product rule problem.

f'(x)=[2\sin(x)\cos(x)]x^{{-3}}+\sin ^{2}(x)(-3)x^{{-4}}\,

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