Calc1.72

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\int {\frac  {x}{1-x^{2}}}\,dx\,

u=1-x^{2}\,

du=-2x\,dx\,

\int {\frac  {x}{1-x^{2}}}\,dx=-{\frac  {1}{2}}\int {\frac  {du}{u}}=-{\frac  {1}{2}}\ln |1-x^{2}|+C\,

Click here to see this integral done by trigonometric substition.
Click here to see this integral done by partial fractions.


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