VC4.6

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Let the given curve be C and let A(0,1,1) and B(1,0,1)be two points on curve C.

Therefore,\int_{C} F\cdot\,dr=\int_{A}^{B} [(2x+yz)i+xzj+(xy+2z)k]\cdot(dxi+dyj+dzk)\,

=\int_{A}^{B} [(2x+yz)dx+xzdy+(xy+2z)dz]\, --(1)

While moving from A to B on the curve C,x varies from 0 to 1,y varies from 1 to 0 and z remains constant.Since z=1,so dz=0.Hence (1) reduces to

\int_{C} F\cdot\,dr=\int_{0}^{1} (2x+y)dx+\int_{1}^{0} xdy+0\,

=\int_{0}^{1} [2x+\sqrt{1-x^2}]dx-\int_{0}^{1}\sqrt{1-y^2} dy\,

=2\int_{0}^{1} xdx+\int_{0}^{1}\sqrt{(1-x^2)}dx-\int_{0}^{1}\sqrt{(1-x^2)}dx=2[\frac{x^2}{2}]_{0}^{1}=1\,

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