VC3.11

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i). div f=div (x^2yi-2xzj+2yzk)=\frac{\partial}{\partial x}(x^2y)+\frac{\partial}{\partial y}(-2xz)+\frac{\partial}{\partial z}(2yz)\,, by definition of divergence.

=2xy+0+2y=2y(x+1)\,

ii). div [(x^2-y^2)i+2xyj+(y^2-2xy)k]=\frac{\partial}{\partial x}(x^2-y^2)+\frac{\partial}{\partial y}(2xy)+\frac{\partial}{\partial z}(y^2-2xy)\,

=2x+2x+0=4x\,

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