Trig3.11

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Prove that \cot \theta+\cot (60+\theta)-\cot (60-\theta)=3\cot 3\theta\,

LHS=\cot \theta+\frac{\cot 60 \cot \theta-1}{\cot 60+\cot \theta}-\frac{\cot 60 \cot \theta-1}{\cot \theta-\cot 60}\,

\cot \theta+\frac{\frac{1}{\sqrt{3}}\cot \theta-1}{\frac{1}{\sqrt{3}}+\cot \theta}-\frac{\frac{1}{\sqrt{3}}\cot \theta-1}{\cot \theta-\frac{1}{\sqrt{3}}}\,

\cot \theta+\frac{\cot \theta-\sqrt{3}}{1+\sqrt{3}\cot \theta}-\frac{\cot \theta+\sqrt{3}}{\sqrt{3}\cot \theta-1}\,

\cot \theta+\frac{(\cot\theta-\sqrt{3})(\sqrt{3}\cot \theta-1)-(\cot \theta+\sqrt{3})(1+\sqrt{3}\cot \theta)}{(\sqrt{3}\cot \theta+1)(\sqrt{3}\cot \theta-1)}\,

\cot \theta-\frac{8\cot \theta}{3\cot^2 \theta-1}\,

\frac{3\cot^3 \theta-9\cot \theta}{3\cot^2 \theta-1}\,

\frac{3(\cot^3 \theta-3\cot \theta)}{3\cot^2 \theta-1}=3\cot 3\theta\, =RHS


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