SF6

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\frac{\Gamma(3)\Gamma(2.5)}{\Gamma(5.5)}\,

Since \Gamma(n+1)=n\Gamma(n)\,,

\frac{2\frac{3}{2}\frac{1}{2}\Gamma(\frac{1}{2})}{\frac{9}{2}\frac{7}{2}\frac{5}{2}\frac{3}{2}\frac{1}{2}\Gamma(\frac{1}{2})} = \frac{2}{\frac{9}{2}\frac{7}{2}\frac{5}{2}} = \frac{2^4}{315} = \frac{16}{315}\,

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