SF5

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\frac{\Gamma(5/2)}{\Gamma(1/2)}\,

Since \Gamma(n+1)=n\Gamma(n)\,,

\frac{\Gamma(\frac{5}{2})}{\Gamma(\frac{1}{2})} = \frac{ \frac{3}{2}\Gamma(\frac{3}{2})}{\Gamma(\frac{1}{2})} = \frac{\frac{3}{2}\frac{1}{2}\Gamma(\frac{1}{2})}{\Gamma(\frac{1}{2})}=\frac{3}{4}\,

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