ODEPR1

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For the equation u''+(\delta + \epsilon \cos t + \epsilon \sin 2t) u = 0\, show that the conditions for parametric resonance are \epsilon = 0\, and \delta=k^2\, or (k+1/2)^2, (k=0,1,2,...)\,.


Let \epsilon=0\,.

Then u''+\delta u=0\, has two L.I. solutions \cos \sqrt{\delta}t\, and \frac{\sin\sqrt{\delta}t}{\sqrt{\delta}}\,.

So the fundamental matrix is X(t)=\begin{bmatrix} \cos\sqrt{\delta}t & \frac{\sin\sqrt{\delta}t}{\sqrt{\delta}} \\ -\sqrt{\delta}\sin\sqrt{\delta}t & \cos\sqrt{\delta}t \end{bmatrix}\,

Notice X(0)=I\, (the identity matrix) so this is a principal fundamental matrix.

The monodromy matrix B\, is the inverse of the fundamental matrix evaluated at zero times the fundamental matrix evaluted at the period of the coefficients.

B=X^{-1}(0)\cdot X(2\pi) = I\cdot X(2\pi) = X(2\pi) = \begin{bmatrix} \cos\sqrt{\delta}2\pi & \frac{\sin\sqrt{\delta}2\pi}{\sqrt{\delta}} \\ -\sqrt{\delta}\sin\sqrt{\delta}t & \cos\sqrt{\delta}2\pi \end{bmatrix}\,

The eigenvalues of B\, are \rho_{1,2}=\phi\pm \sqrt{\phi^2-1}\,.

Also it is true that \phi = \frac{1}{2}\mathrm{Trace}(B) = \cos\sqrt{\delta}2\pi\,.

So now \rho_{1,2}=\cos\sqrt{\delta}2\pi \pm i\sin\sqrt{\delta}2\pi\,.

It is true that -1\le\phi\le 1\,.

In case -1<\phi<1\,, the solutions are bounded, oscillatory, and stable.

In case \phi=-1,\,\,\, \cos\sqrt{\delta}2\pi=-1 \implies \delta=\left(k+\frac{1}{2}\right)^2\,.

In case \phi=1,\,\,\, \cos\sqrt{\delta}2\pi=1 \implies \delta=k^2\,.


Main Page : Ordinary Differential Equations : Parametric Resonance

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