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Find a fundamental matrix and the Wronskian for the following linear system: \begin{cases}x_1'=x_2 \\ x_2'=x_1\end{cases}\,.

The matrix of coefficients A\, is \begin{bmatrix} 0&1\\1&0 \end{bmatrix}\,.

The eigenvalues are \lambda=\pm 1\,.

For \lambda=1\, an eigenvector is u_1=\begin{bmatrix}1\\1\end{bmatrix}\,.

For \lambda=-1\, an eignvector is u_{-1}=\begin{bmatrix}-1\\1\end{bmatrix}\,.

Therefore two linearly independent solutions are:

x^1=e^t\begin{bmatrix}1\\1\end{bmatrix} = \begin{bmatrix} e^t \\ e^t \end{bmatrix}\,

x^2=e^{-t}\begin{bmatrix}-1\\1\end{bmatrix} = \begin{bmatrix} -e^{-t} \\ e^{-t} \end{bmatrix}\,

So a fundamental matrix is X(t)=\begin{bmatrix} e^t & -e^{-t} \\ e^t & e^{-t} \end{bmatrix}\,.

The Wronskian is the determinant of this matrix after evaluation at t=0\,.

W=1+1=2\,


Main Page : Ordinary Differential Equations : Linear Systems

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