ODELC3

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For the first-order system x_1'=x_2, x_2'=-\sin x_1 - x_2 |x_2| + \cos t\,, show that the right-hand side satisfies a Lipschitz condition in the domain |x|\le \beta\, for |t|\le \alpha\,, where \alpha\, and \beta\, are arbitrary but finite numbers. Deduce that the IVP x_1(0)=0\, and x_2(0)=0\, has a unique solution for |t|\le\delta\, and obtain an estimate for \delta\,. By allowing \alpha\, and \beta\, to be as large as possible, attempt to improve your estimate of \delta\,.


f(\vec x,t) = \begin{bmatrix} x_2 \\ -\sin x_1 - x_2|x_2| + \cos t \end{bmatrix}\,

The Lipschitz constant is L=\max\left| \frac{\partial f_1}{\partial x_1} \right| \,.

L=\max\left\{ 1+|\cos x_1| + 2|x_2| \right\}\,

L \le 2 + 2|x_2|\,

If |x|\le \beta\, then

L \le 2(1+\beta)\,


The magnitude of f\, gives an upper bound:

|f(\vec x,t) = |x_2| + |\sin x_1| + |x_2^2| + |\cos t|=\beta^2+\beta+2=M\,


Let \delta = \min\left\{\alpha, \frac{\beta}{\beta^2+\beta+2}\right\}\,


Pick \alpha=\beta=1\, so that \delta=\min\left\{1,\frac{1}{4}\right\}=\frac{1}{4}\,.


Improve the estimate for \delta\, by allowing \alpha\, and \beta\, to be as large as possible.


Maximize \frac{\beta}{\beta^2+\beta+2}\,.


The derivative is \frac{\beta^2+\beta+2 - \beta(2\beta+1)}{(\beta^2+\beta+2)^2} = 0\,.

Just set the numerator equal to 0.

\beta^2+\beta+2 - \beta(2\beta+1)=0\,

-\beta^2+2=0\,

\beta = \sqrt{2}\,


Now let \alpha > \frac{\sqrt{2}}{4+\sqrt{2}}\, so that \delta=\frac{\sqrt{2}}{4+\sqrt{2}}=0.2612\,


Main Page : Ordinary Differential Equations : Lipshitz Conditions

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