ODE2.2

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2y''+y'+4y=0\,

Set up and solve the characteristic equation.

2m^2+m+4=0\,

m = \frac{-1 \pm \sqrt{1-4\cdot8}}{4} =\frac{-1}{4} \pm \frac{i\sqrt{31}}{4}\,

So the general solution is

y(x) = c_1e^{-1/4x}\cos\left(\frac{\sqrt{31}}{4}x\right) + c_2e^{-1/4x}\sin\left(\frac{\sqrt{31}}{4}x\right)\,

Ordinary Differential Equations

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