LinAlg4.2.2

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Find a vector \bar{d}\, which is perpendicular to both \bar{a}=4\bar{i}+5\bar{j}-\bar{k},\bar{b}=\bar{i}-4\bar{j}+5\bar{k}\, and \bar{d}\cdot \bar{c}=21\, where\bar{c}=3\bar{i}+\bar{j}-\bar{k}\,

Let \bar{d}=l\bar{i}+m\bar{j}+n\bar{k}\, where l,m,n are scalars.

Given \bar{a}=4\bar{i}+5\bar{j}-\bar{k},\bar{b}=\bar{i}-4\bar{j}+5\bar{k},\bar{c}=3\bar{i}+\bar{j}-\bar{k}\,

Also given \bar{d}\cdot\bar{c}=21,\bar{d}\cdot\bar{a}=0,\bar{d}\cdot\bar{b}=0\, implies

l(4)+m(5)+n(-1)=0,l(1)+m(-4)+n(5)=0,l(3)+m(1)+n(-1)=21\,

4l+5m-n=0,l-4m+5n=0,3l+m-n=21\,

From the first two equations,we have \frac{l}{1}=\frac{m}{-1}=\frac{n}{-1}=x\,(say)

3(x)-x+x=21,x=7\,

Therefore,the required vector is 7\bar{i}-7\bar{j}-7\bar{k}\,


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