LinAlg4.1.5

From Exampleproblems

If $\bar{OA}=\bar{i}+\bar{j}+\bar{k},\bar{AB}=3\bar{i}+2\bar{j}+\bar{k},\bar{BC}=\bar{i}+2\bar{j}-2\bar{k},\bar{CD}=2\bar{i}+\bar{j}+3\bar{k}\,$ ,then find the position vector of D.

$\bar{OD}=\bar{OA}+\bar{AB}+\bar{BC}+\bar{CD}\,$

$\bar{OD}=(\bar{i}+\bar{j}+\bar{k})+(3\bar{i}+2\bar{j}+\bar{k})+(\bar{i}+2\bar{j}-2\bar{k})+2\bar{i}+\bar{j}+3\bar{k})\,$

$\bar{OD}=7\bar{i}+2\bar{j}+3\bar{k}\,$

Therefore,the position vector of D relative to O as origin is $7\bar{i}+2\bar{j}+3\bar{k}\,$

Main Page:Linear Algebra

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