Geo5.1.25

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Find the equation to the pair of tangents to the parabola y^{2}=6x\, which pass through (-1,2)\,

The equation to the pair of tangents is

[S_{1}]^{2}=SS_{{11}}\,

[y(1)-3(x-1)]^{2}=(y^{2}-6x)(4+6)\,

[y-3x+3]^{2}=10y^{2}-60x\,

y^{2}+9x^{2}+9-6xy-18x+6y=10y^{2}-60x\,

9y^{2}+6xy-9x^{2}-42x-6y-9=0\,


Main Page:Geometry:The Parabola