Geo4.8

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Find the position of the point (3,1) with respect to x^{2}+y^{2}-2x-4y+3=0\,

The centre of the circle is

\left({\frac  {-(-2)}{2}},{\frac  {-(-4)}{2}}\right)\,

\left(1,2\right)\,

Now the distance between the centre and the point is

{\sqrt  {[3-1]^{2}+[1-2]^{2}}}\,

{\sqrt  {5}}\,

Now the radius of the circle is

{\sqrt  {1^{2}+2^{2}-3}}\,

{\sqrt  {2}}\,

Now the distance is greater than the radius,Hence the point lies outside the circle.


Main Page:Geometry:Circles