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Find the equation of the pair of tangents drawn from the point (4,3)\, to the circle x^{2}+y^{2}-2x-4y=0\, and hence find the angle between them.

Given circle is x^{2}+y^{2}-2x-4y=0\,

The equation of the pair of tangents is






Here in the equation,sum of the coefficient of x^{2},y^{2}\, is zero, hence the angle

between the tangents is 90^{\circ }\,

Main Page:Geometry:Circles