Geo4.61

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Find the equation of the chord of the circle x^{2}+y^{2}=15\, having mid point (3,-2).Also find the pole of that chord with respect to the circle.

The equation of the chord having mid point (3,-2) is

x(3)+y(-2)-15=3^{2}+(-2)^{2}-15\,

3x-2y-13=0\,

The pole of the chord with respect to the circle is

From the equation l=3,m=-2,n=-13

Hence

\left(-{\frac  {3(15)}{13}},-{\frac  {(-2)(15)}{-13}}\right)\,

\left({\frac  {-45}{13}},{\frac  {30}{13}}\right)\,


Main Page:Geometry:Circles