Geo4.56

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Find the equation of the chord of the circles i). x^{2}+y^{2}=25\, having (1,-1)\, as its midpoint. ii).x^{2}+y^{2}=81\, having (-2,-3)\, as its midpoint.

i). From the circle g=0,f=0,c=-25\,

Now the equation of the chord of the circle ,midpoint at(1,-1) is

x(1)+y(-1)-25=1^{2}+(-1)^{2}-25\,

x-y-2=0\,

ii). From the given equation

g=0,f=0,c=-81\,

Now the equation of the chord whose midpoint is (-2,-3) is

x(-2)+y(-3)-81=(-2)^{2}+(-3)^{2}-81\,

-2x-3y-13=0\,

2x+3y+13=0\,


Main Page:Geometry:Circles