Geo4.55

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Write down the equation of the chord of the circle x^{2}+y^{2}-2x-4y-20=0\, bisected at the point (2,0).

Given circle is x^{2}+y^{2}-2x-4y-20=0\,

The equation of the chord bisected at (2,0) is

S_{1}=S_{{11}}\, where g=-1,f=-2,c=-20\,

x(2)+y(0)-1(x+2)-2(y+0)-20=2^{2}+0^{2}-2(2)-4(0)-20\,

2x-x-2-2y-20=4-4-20\,

x-2y-2=0\,


Main Page:Geometry:Circles