Geo4.5

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Find the centre and radius of the circle 5x^{2}+5y^{2}-2x-3y=0\,

Rearranging the coefficients in the given circle equation,we get

x^{2}+y^{2}-{\frac  {2}{5}}x-{\frac  {2}{5}}y=0\,

Now the centre of the circle is

\left({\frac  {-(-1)}{5}},{\frac  {-(-1)}{5}}\right)\,

\left({\frac  {1}{5}},{\frac  {1}{5}}\right)\,

Radius of the circle is

{\sqrt  {({\frac  {1}{5}})^{2}+({\frac  {1}{5}})^{2}}}\,

{\sqrt  {{\frac  {2}{25}}}}\,

{\frac  {{\sqrt  {2}}}{5}}\,


Main Page:Geometry:Circles