Prove that the tangent to the circle at (1,-2) also touches the circle and find the point of contact.
Centre of the given first circle is (0,0) and radius is
Slope of the line joining the centre and (1,-2) is
Now the slope of the tangent is 1/2.
The equation of the tangent which has a point (1,2) and slope of -1/2 is
Hence the equation of the tangent is x-2y-5=0\,</math>
Now the centre of the second circle is (4,-3) and radius is
The distance from the centre to the line x-2y-5=0 is
Hence the distance from the centre to the line is equal to the radius,hence it touches the second circle.
Let(x1,y1) be the point of contact.
The distance between centre and the point is equal to radius,
The point lies on the tangent,
Hence the value of x1=3.
Now the point of contact is (3,-1).