Geo3.14

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Prove that the pair of lines (a-\lambda)x^2+2hxy+(b-\lambda)y^2=0\, is equally inclined with the pair ax^2+2hxy+by^2=0\,

Equation to the pair of angle of bisectors of (a-\lambda)x^2+2hxy+(b-\lambda)y^2=0\, is

\frac{x^2-y^2}{(a-\lambda)-(b-\lambda)}=\frac{xy}{h}\,

\frac{x^2-y^2}{a-b}=\frac{xy}{h}\,

which is also the equation tot he angle bisectors of ax^2+2hxy+by^2=0\,

Hence the given two pairs of lines are equally inclined.


Main Page:Geometry:Straight Lines-II

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