Geo2.34

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Find the equation of the straight line passing through the point of intersection of the lines 5x-3y-3=0,4x+y-1=0\, and passing through the point (0,2)\,

The equation of the line passing thro the given lines' point of intersection is

k_1(5x-3y-3)+k_2(4x+y-1)=0\, where k_1,k_2\, are any non-zero constants.

This line passes thro' (0,2)\,

Hence k_1(5(0)-3(2)-3)+k_2(4(0)+2-1)=0\,

-9k_1+k_2=0,k_2=9k_1\,

Therefore,the equation of the line is k_1(5x-3y-3)+9k_1(4x+y-1)=0\,

5x-3y-3+36x+9y-9=0\,

41x+6y-12=0\,

Main Page:Geometry:Straight Lines-I

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