Geo2.21

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Find the equation of the straight line in symmetric form having slope \frac{-1}{\sqrt{3}}\, and passing through (-2,0)\,.

y-0=\frac{-1}{\sqrt{3}}(x-(-2))\,

\sqrt{3}y=-x+2\,

\frac{y}{1}=\frac{x+2}{\sqrt{3}}\,


Main Page:Geometry:Straight Lines-I

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