Geo2.13

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Find the equation of the straight line passing through (4,-3)\, and perpendicular to the line joining (1,1),(2,3)\,.

The slope the line joining (1,1) and (2,3) is

{\frac  {3-1}{2-1}}=2\,

Slope of the require line is -1/2 Now the equation is

y-(-3)={\frac  {-1}{2}}(x-4)\,

2y+6=-x+4\,

2y-x+2=0\,


Main Page:Geometry:Straight Lines-I