# Geo2.13

Find the equation of the straight line passing through $(4,-3)\,$ and perpendicular to the line joining $(1,1),(2,3)\,$.

The slope the line joining (1,1) and (2,3) is

$\frac{3-1}{2-1}=2\,$

Slope of the require line is -1/2 Now the equation is

$y-(-3)=\frac{-1}{2}(x-4)\,$

$2y+6=-x+4\,$

$2y-x+2=0\,$

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