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Find the equation of the straight line making an angle of 120^{\circ }\, with the X-axis in positive direction and passing through the point (0,-2)\,

Slope of the straight line is

m=\tan 120^{\circ }\,

m={\frac  {-1}{{\sqrt  {3}}}}\,

The equation of straight line passing through (x1,y1) and slope m is


y+2={\frac  {-1}{{\sqrt  {3}}}}(x-0)\,

{\sqrt  {3}}y+2{\sqrt  {3}}+x=0\,

Main Page:Geometry:Straight Lines-I