DO6

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$D \sin x = (\lambda_3 + \lambda_2^2 +\lambda_1 +\lambda_1^2 ) \sin x$

$λ 1 sin x = cos x$

$\lambda_1^2 \sin x = \cos^2 x$

$\lambda_2^2 \sin x = \sin^2 x$

$λ 3 sin x = - cos x$

$\therefore D \sin x = -\cos x + \sin^2 x + \cos^2 x + \cos x = 1$

Main Page : Ordinary Differential Equations : Differential Operators

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