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Find the extremals of \int_a^b (y^2 +y'^2 + 2y e^x) \,dx\,.

The Euler-Lagrange equations are in general for the integrand functional L\,

\frac{\partial L}{\partial y} - \frac{d}{dx}\frac{\partial L}{\partial y'} + \frac{d^2}{dx^2}\frac{\partial L}{\partial y''} - \frac{d^3}{dx^3}\frac{\partial L}{\partial y'''} +...+(-1)^k\frac{d^k}{dx^k}\frac{\partial L}{\partial y^{(k)}}=0\,.

So in this problem the EL-equation is

\frac{\partial L}{\partial y} - \frac{d}{dx}\frac{\partial L}{\partial y'}=0\,.

 2y + 2e^x - \frac{d}{dx} 2y' =0\,

 2y + 2e^x - 2y'' = 0\,

 y'' - y = e^x\,

The characteristic equation is m^2-1=0, m=\pm 1\,

 y_h = c_1 e^x + c_2 e^{-x}\,

 y_p = A x e^x\,

 y_p' = A x e^x + A e^x\,

 y_p'' = A x e^x + A e^x + A e^x\,

 y_p'' - y_p = 2A e^x = e^x, A=\frac{1}{2}\,

 y_p = \frac{1}{2} x e^x\,

 y(x) = c_1 e^x + c_2 e^{-x} + \frac{1}{2} x e^x\,

Main Page : Calculus of Variations

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