CalcS2

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Find the upper limit of the sequence \left\{x_{n}\right\}_{{n=1}}^{\infty },x_{n}=(-1)^{n}\left({\frac  {2n}{n+1}}\right)\,

For n even, \left({\frac  {2n}{n+1}}\right)=2-{\frac  {1}{n+1}}\to 2\, as n\to \infty \,.

So the upper limit is 2.



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