# Calc6.73

Discuss the convergence or divergence of the series .

This series looks tricky. Instinctively, since we have on the bottom, we should think this series is going to converge, even with the in the numerator. But, let us use the root test to find out for sure.

This limit looks to be 0, and in fact it is, but how can we show that. The trick is that as n goes to infinity, it can be arbitrarily large. We know that

The thing here is that I can make K as small as I want. For here, making it suffices. Since we are taking the limit as n goes to infinity, we can assume . If this is true, then in changing to , we multiplied by at least . So, we can bring a outside of the square root, though we can bring out an arbitrarily small number by assuming n is as big as we choose. Thus, we have

Thus, this series converges by the root test. Also, note that the series

converges which we can prove easily by assuming n is even bigger and pulling out an even smaller constant to make up for any .