Calc6.23

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Discuss the convergence or divergence of the series \sum_{n=1}^{\infty}\frac{n+4}{(n+2)(n+1)} .

Another comparison test we can use is the limit comparison test. To do this test, we compare two series by looking at the ratio of their terms as n\rightarrow \infty. If this term is a finite positive number, then both series either converge or diverge.

\lim_{n\rightarrow \infty}\frac{\frac{1}{n}}{\frac{n+4}{(n+2)(n+1)}}=\lim_{n\rightarrow \infty}\frac{(n+2)(n+1)}{n(n+4)}=1\,

Since this is a finite, positive number, then both \sum_{n=1}^{\infty}\frac{n+4}{(n+2)(n+1)} and \sum_{n=1}^{\infty}\frac{1}{n} converge or both diverge. We know that \sum_{n=1}^{\infty}\frac{1}{n} diverges so our series also diverges.


Main Page : Calculus

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