Calc2.23

From Exampleproblems

Find the derivative of $f(x)\,$ with respect to $x\,$ : $f(x)=\sin (\cos (\tan x))\,$

Again, we have a chain rule inside of a chain rule.

$f'(x)=\cos (\cos (\tan x))\frac{d}{dx}\cos (\tan x)\,$

$f'(x)=\cos (\cos (\tan x))(-\sin (\tan x))\frac{d}{dx}\tan x\,$

$f'(x)=\cos (\cos (\tan x))(-\sin (\tan x))(\sec^2x)\,$