Calc2.11

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Find the derivative of f(x)\, with respect to x\,: f(x)=8x^5+4x^4+6x^3+x+7\,

For this problem, just use the power rule on every term seperately because the derivative of a sum is equal to the sum of the derivatives of the parts.

f'(x)=8(5)x^{5-1}+4(4)x^{4-1}+6(3)x^{3-1}+x^{1-1}\,

Remember anything to the 0\, power other than 0\, is just 1\, so x^{1-1}=x^0=1\,. Simplify the exponents and constants and we get

f'(x)=40x^4+16x^3+18x^2+1\,


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