# Calc1.73

From Example Problems

Since , we can use the method of partial fractions to compute this integral.

Since this is true for all values of , pick values which will cause one of or to cancel out to find the other.

Let , then

Let , then

Thus, the integral is split up into two integrals

Click here to see this integral done by substitution.

Click here to see this integral done by trigonometric substition.