# Calc1.15

From Example Problems

The key to this problem is realizing that we can split up into two fractions. This method is the method of **Partial Fractions**. We know

Now, it is known that we can split this up into two fractions, one with a base of and the other with base . Let

Multiplying to get a common denominator and equating numerators gives us

Here, notice that this decomposition must be true for all so we can solve for and easily by picking values for .

Let , then which gives

Let , then which gives

So our integral becomes

This is now an integral for which we have a formula.