CVPL2

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Deflate z^{3}+(2-i)z^{2}-2iz\,

=z\left(z^{2}+(2-i)z-2i\right)\,

The roots are z=0,{\frac  {-(2-i)\pm {\sqrt  {(2-i)^{2}+8i}}}{2}}\,

To find {\sqrt  {3+4i}}\,, set up the equation (a+bi)^{2}=3+4i\, to get {\sqrt  {3+4i}}=2+i\,.

The factored form is z(z+2)(z-i)\,

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