CVEL9

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(1+i)^i\, on the principal branch.

(1+i)^i = e^{i\,{\rm Ln}(1+i)}

{\rm Ln}(1+i) = \ln|1+i| + i\,{\rm Arg}(1+i) = \ln\sqrt{2} + i\,\frac{\pi}{4}

Therefore,

(1+i)^i = e^{i\,{\rm Ln}(1+i)} = e^{i\left(\ln(\sqrt{2}) + i\,\pi/4\right)} 
= e^{-\pi/4}\left(\cos(\ln\sqrt{2}) + i\,\sin(\ln\sqrt{2})\right)

Complex Variables
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