CVD3

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Show that $\lim_{z\to 0} \frac{\sin z}{z} = 1\,$

$\lim_{z\to 0} \frac{\sin z}{z} = \lim_{z\to 0} \frac{\sin z - \sin 0}{z} = \sin'(0) = \cos(0) = 1\,$

Main Page : Complex Variables : Differentiation

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