CVCI1

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\oint_{|z|=2} \frac{1-2z}{z(z-1)(z-3)} dz\,

=\oint_{|z|=2} \frac{1-2z}{z^3-4z^2+3} dz = 2\pi i \sum \mathrm{Res}\,

The integrand has simple poles at z=0,1,3\,. Only 0 and 1 are within the contour, so

\oint_{|z|=2} \frac{1-2z}{z(z-1)(z-3)} dz = 2\pi i (\mathrm{Res}_{z=0} + \mathrm{Res}_{z=1} )\,

=2\pi i\left(\frac{1-2z}{3z^2-8z+3}\Big|_{z=0} + \frac{1-2z}{3z^2-8z+3}\Big|_{z=1}\right)\,

=2\pi i \left(\frac{1}{3} + \frac{1}{2}\right) = \frac{5}{3}\pi i\,

Main Page : Complex Variables : Contour Integrals

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