# CV20

Find the equation of the straight line joining the points$(-9+6i),(11-4i)\,$

in the Argand plane.

From the complex numbers,we can derive the points as $(9,6),(11,-4)\,$.

Let the points be $A(9,6),B(11,-4)\,$.

Now the straight line joining these two points is as below

$\overline{AB}=(y-6)=\left(\frac{-4-6}{11-9}\right)(x-9)\,$

Simplifying the fraction $\overline{AB}=(y-6)=\left(\frac{-10}{2}\right)(x-9)\,$

$\overline{AB}=(y-6)=(-5)(x-9)\,$

$\overline{AB}=(y-6)=-5x+45\,$

The straight line equation is $\overline{AB}=y+5x-51=0\,$

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