Bilinear form
From Exampleproblems
In mathematics, a bilinear form on a vector space V over a field F is a mapping V × V → F which is linear in both arguments. That is, B : V × V → F is bilinear if the maps
are linear for each v in V. This definition applies equally well to modules over a commutative ring with linear maps being module homomorphisms.
Note that a bilinear form is a special case of a bilinear operator.
When F is the field of complex numbers C one is often more interested in sesquilinear forms. These are similar to bilinear forms but are conjugate linear in one argument instead of linear.
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Coordinate representation
If V is finite-dimensional with dimension n then any bilinear form B on V can represented in coordinates by a matrix B relative to some ordered basis {ei} for V. The components of the matrix B are given by Bij = B(ei,ej). The action of the bilinear form on vectors u and v is then given by matrix multiplication:
where ui and vj are the components of u and v in this basis.
Maps to the dual space
Every bilinear form B on V defines a pair of linear maps from V to its dual space V*. Define
by
- B1(v)(w) = B(v,w)
- B2(v)(w) = B(w,v)
This is often denoted as
- B1(v) = B(v, − )
- B2(v) = B( − ,v)
where the (–) indicates the slot into which the argument is to be placed.
If V is finite-dimensional then one can identify V with its double dual V**. One can then show that B2 is the transpose of the linear map B1 (if V is infinite-dimensional then B2 is the transpose of B1 restricted to the image of V in V**). Given B one can define the transpose of B to be the bilinear form given by
- B * (v,w) = B(w,v).
If V is finite-dimensional then the rank of B1 is equal to the rank of B2. If this number is equal to the dimension of V then B1 and B2 are linear isomorphisms from V to V*. In this case B is said to be nondegenerate.
Given any linear map A : V → V* one can obtain a bilinear form B on V via
- B(v,w) = A(v)(w)
This form will be nondegenerate iff A is an isomorphism.
Symmetry
A bilinear form B : V × V → F is said to be:
- symmetric if B(v,w) = B(w,v) for all
- skew-symmetric if B(v,w) = − B(w,v) for all
(this is called skew-symmetric by mathematicians and antisymmetric by physicists)
- alternating if B(v,v) = 0 for all
Every alternating form is skew-symmetric; this may be seen by expanding
- B(v+w,v+w).
If the characteristic of F is not 2 then the converse is also true (every skew-symmetric form is alternating). If, however, char(F) = 2 then a skew-symmetric form is the same thing as a symmetric form and not all of these are alternating.
A bilinear form is symmetric (resp. skew-symmetric) iff its coordinate matrix (relative to any basis) is symmetric (resp. skew-symmetric). A bilinear form is alternating iff its coordinate matrix is skew-symmetric and the diagonal entries are all zero (which follows from skew-symmetry when char(F) ≠ 2).
A bilinear form is symmetric iff the maps
are equal, and skew-symmetric iff they are negatives of one another. If char(F) ≠ 2 then one can always decompose a bilinear form into a symmetric and an skew-symmetric part as follows
where B* is the transpose of B (defined above).
Relation to tensor products
By the universal property of the tensor product, bilinear forms on V are in 1-to-1 correspondence with linear maps V ⊗ V → F. If B is a bilinear form on V the corresponding linear map is given by
The set of all linear maps V ⊗ V → F is the dual space of V ⊗ V, so bilinear forms may be thought of as elements of
Likewise, symmetric bilinear forms may be thought of as elements of S2V* (the second symmetric power of V*), and alternating bilinear forms as elements of Λ2V* (the second exterior power of V*).
