Alg9.4.7

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Simplify $\log_{0.01}(0.00001)\,$

Simplifying the value,we get

$\log_{0.01}(0.00001)=\log_{\frac{1}{100}}(\frac{1}{1}{100000})\,$

$\log_{10^{-2}}(10^{-5})\,$

Since the bases are equal,the solution is

$\frac{-5}{-2}\,$

$\frac{5}{2}\,$

Main Page:Algebra:Logarithms

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