Alg9.4.32

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Find x if \log_{10} [98+\sqrt{x^2-12x+36}]=2\,

Taking out the logarithm

98+\sqrt{x^2-12x+36}=10^2\,

\sqrt{x^2-12x+36}=2\,

Squaring on both sides,we get

x^2-12x+36-4=0\,

Solving

x^2-12x+32=0\,

(x-8)(x-4)=0\,

Hence the values of x are 8 and4

Main Page:Algebra:Logarithmic

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