Alg8.6

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Find the sum of all natural numbers between 1\, and 100\, which are multiples of 3\,

Here

a=3,d=3,l=99\,

That is 99=3+(n-1)3\,

99=3n,n=33\,

Therefore S_{33}=\frac{33}{2}[3+99]=1683\,


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