Alg7.16

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Let G be a group such that (ab)2 = a2b2 for all a,b\in G. Prove G is abelian.

abab=(ab)^2=a^2b^2 \Rightarrow a^{-1}(abab)b^{-1}=a^{-1}(a^2b^2)b^{-1} \Rightarrow ba=ab\,

Therefore, every a\in G commutes with every other element of the group.


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