Alg6.11

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Find the value of x if the area of the triangle formed by (10,2),(-3,-4),(x,1)\, is 5units.

The area of triangle is

\frac{1}{2}|[10(-4-1)-3(1-2)+x(2+4)]|=5\,

\frac{1}{2}|-50+3+6x|=5\,

6x-47=10\,

x=\frac{57}{6}\,

x=\frac{19}{2}\,

Hence the value of x is 19/2units.


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