Alg6.11

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Find the value of x if the area of the triangle formed by (10,2),(-3,-4),(x,1)\, is 5units.

The area of triangle is

{\frac  {1}{2}}|[10(-4-1)-3(1-2)+x(2+4)]|=5\,

{\frac  {1}{2}}|-50+3+6x|=5\,

6x-47=10\,

x={\frac  {57}{6}}\,

x={\frac  {19}{2}}\,

Hence the value of x is 19/2units.


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