Alg6.1.2

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Solve (a^2)(i^{6})+(b^2)(i^{8})\,

Readjusting the exponents of i in the expression (a^2)((i^{2})^{3})+(b^2)((i^{2})^{4})\,

Now Substituting the value of i^{2}\, whose value is -1\,

(a^2)((-1)^{3})+(b^2)((-1)^{4})\,

The result is (a^2)(-1)+(b^2)(1)\,

b^2-a^2\,

Further simplifying (b+a)(b-a)\,


Main Page : Algebra : Complex Numbers

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