Alg3.6.7

Solve $6x^{2/3}-11x^{1/3}+4=0\,$

Substitute $w\,$ for $x^{1/3}\,$

Now rewrite the equation

$6w^2-11w+4=0\,$

$w=\frac{4}{3}\,$ and $w=\frac{1}{2}\,$

So $x^{1/3}=\frac{4}{3}\,$ and $x^{1/3}=\frac{1}{2}\,$

$(x^{1/3})^3=(\frac{4}{3})^3\,$ and $(x^{1/3})^3=(\frac{1}{2})^3\,$

$x=\frac{64}{27}\,$ and $x=\frac{1}{8}\,$