Alg10.4

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Find the middle terms of the expansion of (3x+\frac{1}{2x})^7\,

The expansion contains 8 terms in it.Therefore,the middle terms are 4th and 5th terms.

T_4=T_{3+1}=7\!C_3 \cdot (3x)^{7-3}\cdot(\frac{1}{2x})^3\,

T_4=7\!C_3 \cdot81x^4\cdot\frac{1}{8x^3}=7\!C_3 \frac{81}{8}x\,

The next middle term is T_5=T_{4+1}=7\!C_4\cdot(3x)^{7-4}\cdot(\frac{1}{2x})^4\,

T_5=7\!C_4 \cdot27x^3\cdot\frac{1}{16x^4}=7\!C_4\cdot\frac{27}{16x}\,


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