Alg10.14

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Find the term containing x^5\, in the expansion of (x-\frac{1}{x})^{11}\,

T_{r+1}=11\!C_r \cdot x^{11-r}\cdot (\frac{-1}{r})^r=11\!C_r\cdot x^{11-2r}\cdot(-1)^r\,

Since we need to find the term containing x^5\,is 11-2r=5,r=3\,

Hence T_{r+1}=11\!C_3 x^5 (-1)^3=-\frac{11\cdot 10 \cdot 9 \cdot x^5}{3\cdot 2\cdot 1}=-165x^5\,


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